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Ravens' Boldin earns AFC offensive award

Baltimore Ravens' Anquan Boldin is congratulated by head coach John Harbaugh after scoring his third touchdown against the Cleveland Browns at M & T Bank Stadium in Baltimore on September 26, 2010. UPI/Kevin Dietsch
Baltimore Ravens' Anquan Boldin is congratulated by head coach John Harbaugh after scoring his third touchdown against the Cleveland Browns at M & T Bank Stadium in Baltimore on September 26, 2010. UPI/Kevin Dietsch | License Photo

NEW YORK, Sept. 29 (UPI) -- Baltimore wide receiver Anquan Boldin was given the AFC offensive player of the week award Wednesday for his three-touchdown effort last weekend.

Kansas City linebacker Tamba Hali earned the defensive award and Buffalo kick returner C.J. Spiller the special teams award.

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Boldin's TD catches were among eight receptions he had for 142 yards in the Ravens' 24-17 victory over Cleveland. During the game, he became the quickest player in NFL history to reach the 600-reception plateau (98 games). It is the first time he's won the weekly honor.

Hali recorded three sacks and forced a fumble in the Chiefs' 31-10 win over San Francisco. It's also his first time winning the weekly award.

Spiller set a Buffalo rookie record with 189 kickoff return yards, including a 95-yard TD run, in a 38-30 loss to New England. He also caught a 5-yard touchdown pass.

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