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Chayce Beckham wins 'American Idol' Season 19

Chayce Beckham won American Idol Season 19 with Willie Spence in second place and Grace Kinstler in third. Image courtesy of ABC
Chayce Beckham won "American Idol" Season 19 with Willie Spence in second place and Grace Kinstler in third. Image courtesy of ABC

May 24 (UPI) -- Chayce Beckham was crowned the winner of American Idol Season 19, the fourth season to air on ABC.

Beckham won over Willie Spence, who came in second place, and Grace Kinstler, who came in third place on Sunday.

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Beckham and Spence said they loved each other before host Ryan Seacrest announced the winner, which was decided by a nationwide vote.

The singer then performed his original song, titled "23," amid confetti.

The Season 19 finale also featured performances from American Idol judges Katy Perry, Luke Bryan and Lionel Richie.

The Top 9 contestants took the stage to perform alongside Lindsey Buckingham, Alessia Cara, Luke Combs, Sheryl Crow, Fall Out Boy, Mickey Guyton, Chaka Khan, Leona Lewis and Macklemore.

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