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Grammys 2018: Lady Gaga, Pink, Little Big Town to perform

Lady Gaga will perform a track from her Grammy-nominated album "Joanne."

By
Annie Martin
Lady Gaga will perform a track from her album Joanne at the 2018 Grammy Awards. File Photo by Christine Chew/UPI
Lady Gaga will perform a track from her album "Joanne" at the 2018 Grammy Awards. File Photo by Christine Chew/UPI | License Photo

Jan. 4 (UPI) -- Lady Gaga and Pink are among the 2018 Grammy Awards performers.

The Recording Academy announced in a press release Thursday that the singers will take the stage at the awards show Jan. 28 at Madison Square Garden in New York.

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Little Big Town, Childish Gambino, Patti LuPone and Ben Platt will also perform. Late Late Show host James Corden will host the ceremony, which is scheduled to air at 7:30 p.m. ET on CBS.

Lady Gaga, who is nominated for Best Pop Solo Performance for "Million Reasons," will perform a track from her album Joanne, which is up for Best Pop Vocal Album. Pink is also nominated for Best Pop Solo Performance for "What About Us."

"I'm humbled & grateful that my album 'Joanne' was nominated & also my song 'Million Reasons,'" Lady Gaga tweeted after the 2018 nominees were announced in November. "Thank u so much Monsters & Grammy Voters for believing in this music and me."

The 2018 ceremony will mark Childish Gambino's first performance at the Grammys. The 34-year-old singer and actor, born Donald Glover, is up for five awards, including Album of the Year for Awaken, My Love!

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Jay-Z leads the pack of nominees with eight nominations, followed by Kendrick Lamar with seven and Bruno Mars with six. Adele dominated the 2017 ceremony with five wins, including Album of the Year for 25.

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