Jack Sock among first-round ATP winners in New Zealand

Jan. 6, 2014 at 7:14 AM
| License Photo

AUCKLAND, New Zealand, Jan. 6 (UPI) -- Wild-card invitee Jack Sock needed only 61 minutes Monday to finish off a first-round win at the ATP's Heineken Open in New Zealand.

Sock raced past Adrian Mannarino 6-3, 6-4 behind 11 aces. He saved both break points he faced and ended up winning three-quarters of the points on serve. A break in each set allowed him to claim the win.

Santiago Giraldo had four breaks in a 6-1, 7-6 (7-3) decision over Albert Montanes. Giraldo had 10 aces and allowed Montanes just three break chances.

Horacio Zeballos won two-thirds of the points in the first set to head off to a 6-0, 7-6 (7-1) win over Filippo Volandri.

David Ferrer, No. 3 in the world rankings, is the top seed and defending champion for the Heineken Open.

Related UPI Stories
Latest Headlines
Trending Stories
Alabama football: Crimson Tide host Arkansas, hope to continue momentum from Georgia game
St. Louis Rams' Stedman Bailey fined for 'sleeping' on the job
Toronto Maple Leafs lose in Mike Babcock's debut, earn Montreal Canadians' respect
Johnny Manziel's grandfather loses home in 'suspicious' fire