Ravens' Boldin earns AFC offensive award

Sept. 29, 2010 at 2:40 PM
| License Photo

NEW YORK, Sept. 29 (UPI) -- Baltimore wide receiver Anquan Boldin was given the AFC offensive player of the week award Wednesday for his three-touchdown effort last weekend.

Kansas City linebacker Tamba Hali earned the defensive award and Buffalo kick returner C.J. Spiller the special teams award.

Boldin's TD catches were among eight receptions he had for 142 yards in the Ravens' 24-17 victory over Cleveland. During the game, he became the quickest player in NFL history to reach the 600-reception plateau (98 games). It is the first time he's won the weekly honor.

Hali recorded three sacks and forced a fumble in the Chiefs' 31-10 win over San Francisco. It's also his first time winning the weekly award.

Spiller set a Buffalo rookie record with 189 kickoff return yards, including a 95-yard TD run, in a 38-30 loss to New England. He also caught a 5-yard touchdown pass.

Related UPI Stories
Latest Headlines
Trending Stories
Electronics certification company makes hoverboard burst into flames
Eli Manning explains pout after Denver Broncos' Super Bowl score
Duke's Grayson Allen trips Louisville player
Nicola Griffin to appear in Sports Illustrated swimsuit issue at 56
Larry Sanders considering NBA comeback